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Universidad central
Curso
Métodos estadísticos
Carrera
Ingeniería electrónica
Con el objetivo de realizar un estudio de la actividad de su negocio y de ajustar los salarios, la empresa tierra de la u ha inspeccionado la cantidad de clientes que ingresan a su negocio cada 30 min. De tal manera estudio 30 lapsos de tiempo de 30 min. Cada uno y el resultado fue el siguiente:
5
6
7
7
8
9
3
4
10
4
21
13
20
7
6
25
9
7
10
10
6
9
17
15
14
2
19
9
3
5
ordene tales datos en una distribución de frecuencias, con la siguientes características
debe contener familias o categorías (6)
como limite inferior de la primer familiar utilizar 1
se debe introducir en la tabla todos los elementos vistos en clase.
2—1
3—2
4—2
5—2
6—3
7—4
8—1
9—4
10—3
13—1
14—1
15—1
17—1
19—1
20—1
21—1
25—1
AG= 25-2= 23
Ci= ag/N° familias
CI= 23/6=3,83
L.D
1—4
5—8
9—12
13—16
17—20
21—24
25—28
fi frecuencia absoluta
5+10+7+3+3+1+1=30
Fr= fi/n * 100
5/30 . 100= 16.66%
10/30 . 100=33.333%
7/30 . 100=23.333%
3/30 . 100=10%
3/30 . 100=10%
1/30 . 100=3.333%
1/30 . 100=3.333%
5+10=14
14+7=22
22+3=25
25+3=28
28+1=29
29+1=30
16.66 +33.33=49.99%
49.99 + 23.33=73.33%
73.333+ 10 =83.333%
83.333 +10=93.333%
93.333+3.333=96.666%
96.66 +3.333= 100 %
25+ 5 =30
15+10=25
8+ 7 =15
5 + 3 =8
2+ 3 =5
1 + 1 =2
89.323+ 16.666 =100 %
49.999+ 33.33 =83.323%
26.666 + 23.33 =49.999%
16.66 + 10 = 26.666%
6.66 + 10 =16.66%
3.33 + 3.333 = 6.66%
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Enviado por: Fercho Colombiano Idioma: castellanoPaís: Colombia