# Maths Coursework

Maths Coursework

Beyond Pythagoras

32+42= 52

5cm 9+16= 25

3cm

Area= b x h = 3 x 4 = 6cm2

4cm 2 2

Perimeter= 3+4+5= 12cm

52+122=132

5cm 13cm 25+144+=169

Area= (12 x 5) : 2 = 30cm2

12cm Perimeter= 13+5+12= 30cm

72+242=252

49+576=625

7cm 25cm

Area= (7 x 24) :2= 84cm2

Perimeter= 7+24+25= 56cm

24cm

 No Shortest A Middle B Longest C Area Perimeter 1 3cm 4cm 5cm 6cm2 12cm 2 5cm 12cm 13cm 30cm2 30cm 3 7cm 24cm 25cm 84cm2 56cm 4 9cm 40cm 41cm 180cm2 90cm 5 11cm 60cm 61cm 330cm2 132cm 6 13cm 84cm 85cm 546cm2 182cm 7 15cm 112cm 113cm 840cm2 240cm nth 2n+1 2n2+2n 2n2+2n+1 4n2+6n+2 (4n3+6n2+2n) 2

Nth term:

an2+bn+c

Middle side

12= 8+2b+c

4=2b+c 2

as the second difference = 4 then a=2

sequence= 2n2+bn+c

When n=1 b=4

N=2 b=12

4= 2 x 1 x 1 + b x 1 + c

4=2+b+c 2=b+c 1

--- 4= 2b+c

2=b+c

= 2=b

C=0

Fomula for middle side= 2n2+2n

Large side

A=2 because the second difference is 4

Formula= 2n2+2n+1

Pythagoras rule

(2n+1)2 + (2n2+2n)2 = (2n2+2n +1)x(2n2+2n+1)

(4n2+2n+2n+1+4n4+4n3+4n3+4n2) = (4n4+4n3+2n2+4n3+4n2+2n+2n2+2n+1)

8n2+4n+4n4+8n3+1= 4n4+8n3+8n2+4n+1

Nth term of perimeter

A=4; sequence is 4n2+bn+c

When n is 1 b=12cm

When n is 2 b=30cm

12= 4+b+c

8=b+c

30=16+2b+c

14=2b+c

Formula for the perimeter= 4n2+6n+2

Area

(2n+1)(2n2+2n) = 4n3+4n2+2n2+2n

• 2

4n3+6n2+2n

2

 Enviado por: Clara Idioma: inglés País: España

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