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.
DETERMINACIÓN DE LA GRAVEDAD
La práctica consiste en determinar la fuerza con que la Tierra atrae a un péndulo.
Px = p.sen = m.g.sen . M.g.X/l
F= m.a = m.w2.X M.g.X/l = m.w2.X g/l = w2
W2 = (2 /T)2 g/l = (2 /T)2 g= (2 /T)2 .l
L = Longitud (M)
T= Periodo (S)
G = Gravedad (M/S2)
1º) L = 64cm
T = 1,62 S
G = (2 /1,62S)2 . 0,64m = 9,62 M/S2
2º) L= 27cm
T= 1,08 S
G= (2 /1,08S)2 .0,27m = 9,13 M/S2
3º) L= 133cm
T= 2,32 S
G= (2 / 2,32S)2. 1,33m = 9,85 M/S2
Constante de elasticidad de un muelle
F = -K.X = m.w2. X K. X = m. W2 . X
K = m. W2 W2 = (2 /T)2
K = m . (2 /T)2
M = Kg
T = s
L = m
t = s
W= 2 /T
1º) M= 60gr
L = 54,5 cm
T= 0,88 S
K = 0,06Kg. ( 2 /0,88S)2 = 3,058
t = 22s
Y = a . sen ( w.t + f ) = 0,545 .sen 2,27 .t
V = Dy/Dt = 0,545.2,27 . cos 2,27 .t = 1,237 . cos2,27.t
A = Dv/Dt = 1,237 .2,27 . -sen 2,27.t = -2,8082 . sen2,27.t
2º) M = 110gr
L = 70cm
T = 1,16 s
K = 3,22
t = 29s
y = 0,7. sen1,724.t
v = 1,2 .cos1,724.t
a = -2,0802. Sen1,724.t
3º) M = 250gr
L = 87cm
T = 1,52 s
K = 4,27
t = 38 s
y= 0,87.sen1,315.t
v= 1,144 .cos1,315.t
a = -1,5052 . sen 1,315.t
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Enviado por: | Santos Dominguez |
Idioma: | castellano |
País: | España |