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Ejercicio N°2
Máximo y la geometría
Entre todos los cuadrados el de mínima área es: 2 cm ²
A)_Medida del lado inscripto en función de x
Lc F(x)
w=ñ
X=Lt-ñ ð ñ=Lt-X
Lc= Lado del cuadrado=∂x²+w ²
Lc=∂x²+ñ²
Lc=∂x²+(Lt-x)²
Lc=∂x²+Lt²-2Ltx+x²
Ecuación : Lc=∂2x²-2Ltx+Lt²
Reemplazando; siendo:
X=1cm
Lt=2cm
Lc es igual a: 1,41
B)_Medida del área inscripta en función de x
Ac F(x)
w=ñ
X=Lt-ñ ð ñ=Lt-X Lc=∂x²+ñ²
Ac=Area del cuadrado=Lc.Lc.....=Lc²
Ac=Lc²= (∂x²+ñ²)²
Ac= x²+ñ²
Ac= x²+(Lt-x)²
Ac=x²+Lt²-2Ltx+x²
Ecuación : Ac=2x²-2Ltx+Lt²
Reemplazando; siendo:
X=1cm
Lt=2cm
Ac es igual a: 2cm²
C)_Se obtuvo una función de tipo cuadrática f(x)=ax²+bx+c
C)_Máximos y mínimos
x | Lc | Ac |
0 | 2 | 4 |
0,25 | 1,76 | 3,125 |
0,5 | 1,58 | 2,5 |
0,75 | 1,45 | 1,125 |
1 | 1,41 | 2 |
1,25 | 1,45 | 2,125 |
1,5 | 1,58 | 2,5 |
1,75 | 1,76 | 3,125 |
2 | 2 | 4 |
x € reales {0 <= x <= Lt }
Siendo:Lt=2cm
Máximo en Lc =2cm
Máximo en Ac=4cm²
Minimo en Lc=1.41cm
Minimo en Ac=2cm²
: Lc=∂2x²-2Ltx+Lt²
: Ac=2x²-2Ltx+Lt²
D)_ Tiene máximos y mínimos por ser: función cuadrática,
F)_ Gráfica de: Ac F(x) E)_Gráfica de: Lc F(x)
Ac=2x²-2Ltx+Lt² Lc=∂2x²-2Ltx+Lt²
G)_Si el logo hubiera sido un circulo de 2cm de diámetro
|Diámetro=2cm
r=1cm=x
c=Hipotenusa
c=∂a²+b²
a=b
a=1cm
Lc=c=∂1+1=
C=1,41cm
Area=Lc.Lc=Lc²
Ac=(1,41cm)²
Ac=2cm²
Lc=∂x²+x² Ej :r=1,41cm
Lc=∂2x² A=2cm²
Lc=x∂2
Ac=Lc²
Ac=(∂x²+x²)²
Ac=2x²
Ejercicio : N° 3
a=(10;150)
b=(12;134)
c=(15;95)
(150=a(10-m)²+n
(134=a(12-m)²+n
(95=a(15-m)²+n
(1)-(2) (16=a(10-m)²-a(12-m)²
(1)-(3) (55=a(10-m)²-a(15-m)²
(16=a[(10-m)²-(12-m)²]
(55=a[(10-m)²-(15-m)²]
16=a[(10-m)²-(12-m)²]
55=a[(10-m)²-(15-m)²]
16=-44+4m
16.(-125+10m)=(55-44+4m)
-2000+160m=-2420+220m
-2000+2420=220m-160m
420=m m=7
60
16=a(9-25) a=-1
150=-1(10-7)²+n
150-[-1(10-7)²]=n n=159
A)_Función: y=-1(x-7)²+159
B)_ y=-1(20-7)²+159
y=-10
y=-1(5-7)²+159
y=155
C)_El precio es $7 porque vendería 159miles de unidades
$7. 159000=$113000 Total de la ganancia
$113000+ 40% de la ganancia al precio mayorista=
$113000+$445200=$1558200 Total+40% de la ganancia
Transporte=$79500
Fabricación =$477000
Ganancia =$1558200-$79500-$477000= $1001700
Ejercicio N° 1
d=½gt²+Vit
A)_Si, es una función polinómica
B)_Raices:
X=-b±∂b²-4ac x =-Vi±Vi
2a 10m/s²
X1=-Vi+Vi X1=Raiz=t1=0
10m/s²
X2 =-2Vi X2=Raiz=t2=-2Vi
10m/s² 10m/s²
C)_Son los puntos en el que al valer el tiempo =0; no tiene desarrollo o movimiento alguno el móvil
D)_Es creciente desde: -Vi<t<+infinito
g
Vértice de la curva = -Vi
_Es decreciente desde: -infinito<t<-Vi g
g
E)_
Datos: Vi=10m/s
hi=1m=Factor aditivo corrector de la altura
t=?
h=?
Vf=Vi-½gt
0= Vi-½gt
Vi=½gt
Vi. 2=t t=2 Seg.
G
e=1/2 g t²
h= hi + ½ g t²
h= 1m + ½ 10m/s². 2² seg.²
h=21m
F)_Ecuación de caida libre d= ½ g t² +Vi t
-Gráfica del punto anterior: en función del tiempo(seg)
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Enviado por: | Ser E.t.i.l.a.h. |
Idioma: | castellano |
País: | Argentina |