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PRÁCTICA Nº 15
CÁLCULO DE LA FOCAL DE UNA LENTE
Objetivo:
Hallar la focal de una lente convergente mediante dos procedimientos distintos, como son el procedimiento de Gauss y el método gráfico
Hallar la focal de una lente divergente mediante el ajuste de mínimos cuadrados
Material utilizado para el desarrollo de la práctica :
Para el desarrollo de ésta práctica utilizaremos un banco óptico, una fuente de alimentación, una transparencia objeto, una lente focal +150 mm ( colimador ), una lente convergente incógnita, una lente divergente incógnita, un soporte para diafragma, un diafragma circular y una pantalla
Desarrollo de la práctica:
Comenzaremos la práctica tomando los datos que nos facilitarán el cálculo de la focal de las distintas lentes, es decir, las distancias que existen entre el objeto y la lente ( z1 ) y la distancia existente entre la lente convergente y la pantalla (z2 ). Ëstas distancias se tomarán al menos en 3 posiciones distintas.
A partir de estos datos y siguiendo el método de Gauss realizaremos el estudio gráfico (gráfica adjunta ).
Posteriormente al estudio gráfico, estudiaremos el método teórico:
1r caso: 2do caso:
Z1 = - 145 Z1 = -138
Z2 = 345 Z2 = 372
F'1 = (-145 ) (345) = 107'01*1'00 mm F'1 = (-138 ) (372) = 100'66 * 1,0 mm
- 145 - 345 -138 - 372
3er caso
Z1= -156
Z2 = 290
F'1 = (-156 ) (290) = 101'43 * 1'00 mm
-156- 290
f' (media) = 107'01 + 100'66 + 101'43
3
f' (media ) = 101'39 * 1'00
D= Vmax - Vmin = 103'01 - 101'66 = 1'35
T (%) = 1'35 = 1'33 < 3%
101'39
E = ( 107'09 - 101'39 ) + ( 100'66 - 101'39 ) + ( 101'43 - 101'39 )
3
E = 0'003 f' = 101'390 * 0'003
3.-
Potencia= 1 = 0'098 P(2)= 1 =0'099 P(3)= 1 =0'098
107'01 100'66 101'43
Pmedia = 0'0983^
D= Vmax - Vmin = 0'099 - 0'098 = 0'001
T (%) = 0'001 = 1' 06% < 3
E = ( 0'098 - 0'0983 ) + ( 0'099 - 0'0983 ) + ( 0'098 - 0'0983 ) = 0'0007
3
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Enviado por: Rafa Valero Idioma: castellanoPaís: España