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0 Me sirvió
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CRONOGRAMAS
PARTE A
PARTE B
SALIDA
0
0
0
1
0
0
1
1
0
1
0
0
1
0
1
0
0
1
0
0
0
Cogemos los unos para hacer la ecuación:
Si tenemos muchos unos, se nos complica mucho la ecuación. Por lo que podemos coger los ceros y negar la ecuación que nos sale.
A
B
C
SALIDA
0
0
0
0
1
0
0
1
0
0
0
0
1
1
0
1
1
0
0
1
1
1
0
1
0
1
0
0
0
0
1
1
0
1
1
1
1
1
1
1
1
0
1
0
A
B
C
SALIDA
0
0
0
0
1
0
0
1
1
1
0
1
0
1
0
0
0
0
1
1
0
1
1
1
1
1
1
1
1
0
1
0
A
B
C
SALIDA
0
0
0
1
0
0
1
1
0
1
0
1
0
1
1
1
1
0
0
1
1
0
1
0
1
1
0
0
1
1
1
0
La siguiente función F (A,B,C) tomará el valor “0” cuando la variable B se encuentre en estado “1” y la variable A no esté en ese estado. En los demás casos, la función adquirirá el valor “1”.
Realizar la tabla de la verdad de la función y obtener la expresión mas simplificada de ésta.
A
B
C
SALIDA
0
0
0
1
0
0
1
1
0
1
0
0
0
1
1
0
1
0
0
1
1
0
1
1
1
1
0
1
1
1
1
1
Diseñar un sistema combinacional (cualquier tipo de puerta de dos entradas) de tres señales de entrada (A,B,C) que comande tres lámparas (X,Y,Z), encendiéndolas según las siguientes especificaciones. Montar el circuito de mando.
ENTRADA
SALIDA
A
B
C
X
Y
Z
0
0
0
0
0
0
0
0
1
1
1
0
0
1
0
0
0
1
0
1
1
1
0
1
1
0
0
0
0
0
1
0
1
0
1
0
1
1
0
1
0
0
1
1
1
1
0
0
ENTRADAS
SALIDAS
Ninguna
Ninguna
A solamente
Ninguna
B solamente
Z únicamente
C solamente
X e Y
A y B
X únicamente
B y C
X y Z
A y C
Y únicamente
A, B y C
X únicamente
SALIDA X:
SALIDA Y:
SALIDA Z:
MAPAS DE KARNAUGH
Tienen que estar todas las variables presentes en todos los términos. Hay que agrupar los unos en potencias de dos: 2, 4, 8, 16…etc.
A
B
C
SALIDA
0
0
0
0
0
0
1
0
0
1
0
0
0
1
1
0
1
0
0
1
1
0
1
0
1
1
0
1
1
1
1
1
AB
C
00
01
11
10
0
1
1
1
1
A
B
C
D
0
0
0
0
1
0
0
0
0
0
1
0
1
0
1
0
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Enviado por: Victor Idioma: castellanoPaís: España