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# Estructura Molecular

\!\(\*
RowBox[{
RowBox[{"(*", " ",
StyleBox[\(Ejercicio\ 42\),
FontColor->RGBColor[1, 0, 0]], " ", "*)"}], "\n",
\( (*\ Deducir\ los\ conmutadores\
\(siguientes : \n\t\t\ \([lx, \ y]\)\ y\ [lz, \ z]\)\ *) \),
"\n",
\( (*\ \([lx, y]\)\ *) \), "\n",
\( (*\ lx = \(-\[ImaginaryI]h\) \((y*d\/dz - z*d\/dy)\)\ *) \),
"\n",
\( (*\ \([\(-\[ImaginaryI]h\) \((y*d\/dz - z*d\/dy)\), y]\)\ *) \),
"\n",
RowBox[{
\(ClearAll["\<Global`*\>"]\), "\n",
\(A = \(-\[ImaginaryI]\)*h \((y*D[y\ f[x], z] - z*D[y\ f[x],
y])\)\),
"\n", \(I\ h\ z\ f[x]\), "\n",
\(B = \(-\[ImaginaryI]\)\ h\ y
\((y*\ D[\ f[x], z] - z*\ D[f[x], y])\)\), "\n", "0", "\n",
\((A - B)\), "\n", \(I\ h\ z\ f[x]\), "\n", \(\((A - B)\)/f[x]\),
"\n",
\(I\ h\ z\), "\n", \( (*\ lz, z\ *) \), "\n",
\( (*\ lz = \(-\[ImaginaryI]h\) \((x*d\/dy - y*d\/dx)\)\ *) \),
"\n",
\( (*\ \([\(-\[ImaginaryI]h\) \((x*d\/dy - y*d\/dx)\), y]\)\ *)
\),
"\n", \(ClearAll["\<Global`*\>"]\), "\n",
\(A = \(-\[ImaginaryI]\)*h \((x*D[z\ f[x], y] - y*D[z\ f[x],
x])\)\),
"\n",
RowBox[{"I", " ", "h", " ", "y", " ", "z", " ",
RowBox[{
SuperscriptBox["f", "\[Prime]",
MultilineFunction->None], "[", "x", "]"}]}], "\n",
\(B = \(-\[ImaginaryI]\)\ h\ z
\((x*\ D[\ f[x], y] - y*\ D[f[x], x])\)\), "\n",
RowBox[{"I", " ", "h", " ", "y", " ", "z", " ",
RowBox[{
SuperscriptBox["f", "\[Prime]",
MultilineFunction->None], "[", "x", "]"}]}], "\n", \((A -
B)\),
"\n", "0", "\n", \(\((A - B)\)/f[x]\), "\n", "0"}], "\n",
\( (*\ lz, z\ *) \), " "}]\)

 Enviado por: Elizabeth Arrinda Idioma: castellano País: España

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