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Resolver las ecuaciones con radicales:
1) x +" X - 4 = 4
( " x - 4 ) ² = ( 4 - x ) ²
x - 4 = x² - 8x + 16
0 = x² - 9x + 20
(x - 4) (x - 5)
x - 4 = 0 x - 5= 0
x = 5no
2) " 2x + 3 - " x - 2 = 2
" 2x + 3 = 2 " x - 2
(" 2x + 3) ² = ( 2 " x - 2) ²
2x + 3 = 4 + 4 " x - 2 + x - 2
2x + 3 - 4 - x + 2 = 4 " x - 2
(x - 1) ² = (4 " x - 2) ²
x² + x + 1 = 16 ( x - 2)
x² + x + 1 = 16x - 32
x² - 15x + 33 = 0
(x - 11) ( x - 3) = 0
x - 11= 0 x - 3 = 0
x - 5 = " x - 3
(x - 5) ² = (" x - 3) ²
x ² - 10x + 25 = x - 3
x ² - 11x + 28 = 0
(x - 7) (x - 4) = 0
x = 4 no
"2x + 5 + "x + 2 = 5
("2x +5) ² = (10 - "x + 2) ²
2x + 5 = 10 "x + 2 + x + 27
( x - 22) ² = (10 "x + 2) ²
x² - 44x + 484 = 100 ( x + 2)
x² - 44x + 484 = 100x + 200
x² - 44x + 484- 100x - 200 = 0
x - 144x + 284 = 0
( x - 142) ( x - 2) = 0
x - 142=0 x - 2 = 0
x = 142 no
x = 4
x = 11
x = 3
x = 7
x = 2
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Enviado por: | Green Kitten |
Idioma: | castellano |
País: | Puerto Rico |